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Sum of a Finite Geometric Series

A geometric series adds terms that each multiply by a fixed ratio rr, like 3+6+12+3 + 6 + 12 + \cdots. Adding many terms by hand is slow, so there is a formula.

The sum of the first nn terms is Sn=a1rn1rS_n = a\dfrac{1 - r^n}{1 - r}, where aa is the first term. Identify aa, rr, and nn, then plug in.

Identify the three pieces

The first term is aa. The common ratio rr is any term divided by the one before it. For 3+6+123 + 6 + 12, r=63=2\displaystyle r = \frac{6}{3} = 2.

nn is how many terms you are adding. With those three numbers the formula does the rest.

Applying the formula

Substitute into Sn=a1rn1rS_n = a\dfrac{1 - r^n}{1 - r} and simplify the power rnr^n carefully.

The formula works for any ratio except r=1r = 1 (where every term is the same and you just multiply aa by nn).

Worked examples

Example 1: sum of five terms

Find the sum of the first 5 terms of 3+6+12+3 + 6 + 12 + \cdots

Identify a, r, na=3,;r=2,;n=5a = 3, ; r = 2, ; n = 5
Apply the formula3125123 \cdot \dfrac{1 - 2^5}{1 - 2}
Simplify3311=933 \cdot \dfrac{-31}{-1} = 93

Answer: 9393

Example 2: finding the ratio

What is the common ratio of 5+10+20+5 + 10 + 20 + \cdots?

Divide a term by the previous10÷510 \div 5
Simplify22

Answer: r=2r = 2

Example 3: when the ratio is 1

Find the sum of the first 6 terms of 7+7+7+7 + 7 + 7 + \cdots

Divide a term by the previousr=7÷7=1r = 7 \div 7 = 1
The formula's denominator would be zero1r=01 - r = 0
Every term equals a, so multiply by n767 \cdot 6
Simplify4242

Answer: 4242

Try one yourself

Common questions

How do I find the common ratio?

Divide any term by the term before it. If that ratio is constant, the series is geometric and that value is rr.

What are a, r, and n?

aa is the first term, rr the common ratio, and nn the number of terms being added.

Does the formula work if r = 1?

No — it would divide by zero. If r=1r = 1 every term equals aa, so the sum is simply ana \cdot n.

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