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Special Right Triangles: 30-60-90

A 30-60-90 triangle is a right triangle whose acute angles measure exactly 3030^\circ and 6060^\circ. Because the angles are always the same, the sides are always in the same proportion: x:x3:2xx : x\sqrt{3} : 2x. Know one side and you can find the other two with no Pythagorean theorem and no calculator trig.

Everything hinges on identifying the short leg — the side opposite the 3030^\circ angle. Once you know the short leg is xx, the long leg (opposite 6060^\circ) is x3x\sqrt{3} and the hypotenuse (opposite the right angle) is 2x2x.

The ratio and where each side sits

Sides face their angles: the smallest side is across from the smallest angle. So the short leg xx is opposite 3030^\circ, the long leg x3x\sqrt{3} is opposite 6060^\circ, and the hypotenuse 2x2x is opposite the 9090^\circ angle.

Two relationships fall straight out of the ratio: the hypotenuse is exactly twice the short leg, and the long leg is the short leg times 3\sqrt{3}. Those two sentences are the whole lesson.

The figure pins each side to its angle: the short leg xx faces 3030^\circ, the long leg x3x\sqrt{3} faces 6060^\circ, and the hypotenuse 2x2x faces the right angle.

x3x\sqrt{3}
xx
2x2x
3030^\circ
6060^\circ

Always work through the short leg

Whatever side you are given, find the short leg first, then build the other sides from it. Given the hypotenuse? Divide by 22. Given the long leg? Divide by 3\sqrt{3} (and rationalize: 93=933=33\dfrac{9}{\sqrt{3}} = \dfrac{9\sqrt{3}}{3} = 3\sqrt{3}). Given the short leg? You are already done with step one.

The classic mistake is doubling the short leg to get the long leg. Doubling gives the hypotenuse. The long leg comes from multiplying by 3\sqrt{3}, which is about 1.731.73 — so the long leg is bigger than the short leg but smaller than the hypotenuse, exactly as the ratio says.

How this differs from 45-45-90

A 45-45-90 triangle has two equal legs and ratio x:x:x2x : x : x\sqrt{2} — the only move is multiplying or dividing by 2\sqrt{2}. A 30-60-90 triangle has three different sides, so you must track which leg is which. If you see 2\sqrt{2} in your work on a 30-60-90 problem, you have mixed up the two triangle types.

Worked examples

Example 1: short leg to hypotenuse

The short leg of a 30-60-90 triangle measures 55. Find the hypotenuse.

Write the ratiox:x3:2xx : x\sqrt{3} : 2x
The short leg is xxx=5x = 5
The hypotenuse is twice the short leg2x=2(5)=102x = 2(5) = 10

Answer: 1010

Example 2: hypotenuse to both legs

The hypotenuse of a 30-60-90 triangle measures 1414. Find the short leg and the long leg.

The short leg is half the hypotenusex=142=7x = \dfrac{14}{2} = 7
The long leg is the short leg times 3\sqrt{3}x3=73x\sqrt{3} = 7\sqrt{3}

Answer: Short leg =7= 7, long leg =73= 7\sqrt{3}

Example 3: long leg to short leg

The long leg of a 30-60-90 triangle measures 99. Find the short leg.

The long leg is the short leg times 3\sqrt{3}9=x39 = x\sqrt{3}
Divide both sides by 3\sqrt{3}x=93x = \dfrac{9}{\sqrt{3}}
Rationalize the denominatorx=933=33x = \dfrac{9\sqrt{3}}{3} = 3\sqrt{3}

Answer: x=33x = 3\sqrt{3}

Try one yourself

55
xx
3030^\circ

Common questions

Which side is the short leg?

The side opposite the 3030^\circ angle — the side that does not touch the 3030^\circ vertex. Sides face their angles, so the smallest angle faces the smallest side.

Is the hypotenuse twice the short leg or twice the long leg?

Twice the short leg. The long leg is the short leg times 3\sqrt{3}, which is a different, smaller multiplier than most students expect — about 1.731.73.

What if my answer has a square root in the denominator?

Rationalize it: multiply the top and bottom by the root. For example, 93=933=33\dfrac{9}{\sqrt{3}} = \dfrac{9\sqrt{3}}{3} = 3\sqrt{3}. Answer choices are almost always written in rationalized form.

Why does this shortcut work at all?

A 30-60-90 triangle is half of an equilateral triangle — cut an equilateral triangle down the middle and the hypotenuse is an original side while the short leg is half a side. That is where the 2x2x comes from, and the Pythagorean theorem then forces the long leg to be x3x\sqrt{3}.

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