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Geometric Mean & the Altitude-on-Hypotenuse Relationships

The geometric mean of two numbers aa and bb is ab\sqrt{ab} — you multiply the numbers and take the square root. It is a different kind of average from the one you are used to: the geometric mean of 44 and 2525 is 100=10\sqrt{100} = 10, not 14.514.5.

In geometry this shows up in one very specific place. When you draw the altitude from the right angle of a right triangle to the hypotenuse, that altitude splits the triangle into pieces whose lengths are all connected by geometric means. Learn two rules and every problem in this lesson becomes a multiply-then-square-root exercise.

The setup: three similar triangles

Start with a right triangle and drop the altitude from the right angle straight down to the hypotenuse. The altitude cuts the hypotenuse into two pieces — call them pp and qq — and it cuts the original triangle into two smaller right triangles.

Here is the key fact: the two small triangles are each similar to the original triangle, and to each other. All three triangles have the same angles, so their sides are proportional. The geometric mean relationships below are just those proportions written as equations. The figure shows the altitude hh dropped to the hypotenuse, splitting it into the pieces pp and qq.

pp
qq
hh
AA
DD
BB
CC

Rule 1: the altitude rule

The altitude is the geometric mean of the two hypotenuse pieces: h=pqh = \sqrt{pq}, or equivalently h2=pqh^2 = pq. If the altitude splits the hypotenuse into pieces of length 44 and 99, then h=49=36=6h = \sqrt{4 \cdot 9} = \sqrt{36} = 6.

This is the rule you will use most often. When a problem gives you both pieces of the hypotenuse and asks for the altitude, multiply the pieces and take the square root.

Rule 2: the leg rule

Each leg of the original triangle is the geometric mean of two lengths: the hypotenuse piece next to that leg, and the whole hypotenuse. In symbols, leg=(adjacent piece)(whole hypotenuse)\text{leg} = \sqrt{(\text{adjacent piece}) \cdot (\text{whole hypotenuse})}.

The word adjacent is doing the work here. Each leg touches exactly one of the two hypotenuse pieces — that is the piece you pair with the whole hypotenuse. Students who grab the wrong piece get a wrong answer that still looks reasonable, so always check which piece the leg actually touches.

Worked examples

Example 1: find a geometric mean

Find the geometric mean of 88 and 1818.

Write the formulax=abx = \sqrt{ab}
Substitute the two numbersx=818x = \sqrt{8 \cdot 18}
Multiply, then take the square rootx=144=12x = \sqrt{144} = 12

Answer: 1212

Example 2: the altitude rule

The altitude to the hypotenuse splits the hypotenuse into pieces of length 33 and 1212. Find the altitude hh.

The altitude is the geometric mean of the two piecesh=pqh = \sqrt{pq}
Substituteh=312h = \sqrt{3 \cdot 12}
Simplifyh=36=6h = \sqrt{36} = 6

Answer: h=6h = 6

Example 3: the leg rule

The altitude to the hypotenuse splits it into pieces of length 33 and 99. Find the leg that touches the piece of length 33.

Find the whole hypotenuse3+9=123 + 9 = 12
The leg is the geometric mean of the adjacent piece and the whole hypotenusex=312x = \sqrt{3 \cdot 12}
Simplifyx=36=6x = \sqrt{36} = 6

Answer: x=6x = 6

Try one yourself

Common questions

What is the difference between the geometric mean and the regular average?

The regular average of aa and bb is a+b2\dfrac{a+b}{2} — add and divide. The geometric mean is ab\sqrt{ab} — multiply and square-root. For 33 and 1212, the regular average is 7.57.5 but the geometric mean is 66. Right-triangle altitude problems always use the geometric mean.

How do I know which hypotenuse piece goes with which leg?

Look at the diagram: each leg touches exactly one of the two pieces at the foot of the altitude. Pair the leg with the piece it touches, then multiply that piece by the whole hypotenuse and take the square root.

Do I use the whole hypotenuse or just a piece in the altitude rule?

Just the pieces. The altitude rule is h=pqh = \sqrt{pq} where pp and qq are the two pieces. The whole hypotenuse only appears in the leg rule.

What if the square root does not come out to a whole number?

Leave it as a simplified radical, like 492=62\sqrt{4 \cdot 9 \cdot 2} = 6\sqrt{2}, unless the problem asks for a decimal. Many answers in this lesson are radicals, and that is fine.

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