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Segments, Rays & the Segment Addition Postulate

The Segment Addition Postulate says something you already believe: if point BB sits between AA and CC on a segment, then the two pieces add up to the whole — AB+BC=ACAB + BC = AC. That one equation solves every problem in this lesson.

The real skill is deciding which length is the whole and which lengths are the pieces. Once that is settled, every problem is one of three moves: add the two pieces, subtract a piece from the whole, or solve a short equation when the pieces are written with a variable.

Pieces and the whole

First, a note on notation: AB\overline{AB} with a bar names the segment itself, while ABAB with no bar means its length — a number. The Segment Addition Postulate is a statement about lengths, so it is written without bars: AB+BC=ACAB + BC = AC.

The point in the middle of the betweenness statement is the one splitting the segment. If BB is between AA and CC, then ABAB and BCBC are the pieces and ACAC is the whole. Given both pieces, add to get the whole. Given the whole and one piece, subtract to get the other piece.

When the pieces are expressions

Often the pieces are given as expressions like 2x+12x + 1 and x+4x + 4 with a number for the whole. Set up the same equation — pieces on one side, whole on the other — then combine like terms and solve for xx.

Read the question twice at the end. Some problems ask for xx, but many ask for a length like BCBC, which means one more step: substitute your xx back into the expression for that piece.

The classic trap

The most common mistake is adding two numbers that are not both pieces. If a problem gives AB=25AB = 25 and AC=40AC = 40, then ACAC is the whole — adding gives a wrong answer of 6565. Sketch the segment, label the three points in order, and mark each given length on the sketch before you compute. The picture makes the whole and the pieces obvious.

Worked examples

Example 1: add the pieces

BB is between AA and CC, with AB=13AB = 13 and BC=21BC = 21. Find ACAC.

Segment Addition PostulateAB+BC=ACAB + BC = AC
Substitute the two piecesAC=13+21AC = 13 + 21
AddAC=34AC = 34

Answer: AC=34AC = 34

Example 2: subtract a piece from the whole

A straight trail runs from trailhead PP through checkpoint QQ to summit RR. The whole trail is 3131 miles and the leg from PP to QQ is 1414 miles. How long is the leg from QQ to RR?

The two legs make up the whole trailPQ+QR=PRPQ + QR = PR
Substitute what is known14+QR=3114 + QR = 31
Subtract 1414 from both sidesQR=17QR = 17

Answer: QR=17QR = 17 miles

Example 3: pieces with a variable

KK is between JJ and LL, with JK=2x+1JK = 2x + 1, KL=x+4KL = x + 4, and JL=23JL = 23. Find xx.

Segment Addition PostulateJK+KL=JLJK + KL = JL
Substitute(2x+1)+(x+4)=23(2x + 1) + (x + 4) = 23
Combine like terms3x+5=233x + 5 = 23
Subtract 55 from both sides3x=183x = 18
Divide by 33x=6x = 6

Answer: x=6x = 6

Try one yourself

1313
2121
AA
BB
CC

Common questions

How do I know which length is the whole?

Use the betweenness statement. If BB is between AA and CC, the whole runs between the two outer letters, so ACAC is the whole and ABAB and BCBC are the pieces. When in doubt, sketch the three points in order and label the given lengths.

What is the difference between AB\overline{AB} and ABAB?

AB\overline{AB} with a bar is the segment — a geometric object. ABAB with no bar is its length — a number. You add and subtract lengths, so the postulate is written without bars.

The problem asked for BCBC but I found xx. Am I done?

Not yet. Solving the equation gives xx, but the question asks for a length. Substitute xx back into the expression for BCBC and simplify — that number is the answer.

Does the postulate work if BB is not between AA and CC?

No. The equation AB+BC=ACAB + BC = AC requires BB to be on segment AC\overline{AC}, between the endpoints. If BB is off the segment, the two smaller lengths no longer add up to ACAC.

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