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Volume of Cones & Spheres

Cones and spheres each get their own volume formula. A cone is an ice-cream-cone shape — a circular base that narrows to a point. A sphere is a ball — perfectly round in every direction. Their formulas are V=13πr2h\displaystyle V = \frac{1}{3} \pi r^2 h for a cone and V=43πr3\displaystyle V = \frac{4}{3} \pi r^3 for a sphere.

Both formulas connect back to the cylinder. A cone with the same base and height as a cylinder holds exactly one third of the cylinder's volume — pour three cones of water into the matching cylinder and it fills to the top. The sphere has no separate height at all; its size is set entirely by the radius, which is why rr shows up cubed.

The two formulas

Cone: V=13πr2h\displaystyle V = \frac{1}{3} \pi r^2 h. It's the cylinder formula πr2h\pi r^2 h with a 13\displaystyle \frac{1}{3} in front, because the cone narrows to a point instead of keeping its full base all the way up. The cone below is labeled with the two measurements it needs — the base radius rr and the height hh.

Sphere: V=43πr3\displaystyle V = \frac{4}{3} \pi r^3. There is no hh in this formula — a sphere is the same distance from its center in every direction, so the radius does all the work.

Keep the fractions straight: the cone takes 13\displaystyle \frac{1}{3}, the sphere takes 43\displaystyle \frac{4}{3}. Writing the formula down before substituting is the cheapest insurance there is.

hh
rr

Squared vs. cubed

In the cone formula the radius is squared, because πr2\pi r^2 is the area of the circular base. In the sphere formula the radius is cubed. If you catch yourself writing r2r^2 inside a sphere problem, stop and fix it — 33=273^3 = 27, not 99, and that difference changes everything downstream.

A sphere has just one measurement, the radius rr shown below — no separate height — which is why rr is the only length in its formula.

As with cylinders, watch for the diameter trap: if the problem gives a diameter, halve it to get the radius before you substitute.

rr

Worked examples

Example 1: volume of a cone

Find the volume of a cone with radius 22 and height 66. Use π3.14\pi \approx 3.14.

Write the formulaV=13πr2hV = \dfrac{1}{3} \pi r^2 h
Substitute the valuesV=133.14226V = \dfrac{1}{3} \cdot 3.14 \cdot 2^2 \cdot 6
Square the radiusV=133.1446V = \dfrac{1}{3} \cdot 3.14 \cdot 4 \cdot 6
Multiply, taking one third at the endV=1375.36=25.12V = \dfrac{1}{3} \cdot 75.36 = 25.12

Answer: V=25.12V = 25.12

Example 2: volume of a sphere

Find the volume of a sphere with radius 33. Use π3.14\pi \approx 3.14.

Write the formulaV=43πr3V = \dfrac{4}{3} \pi r^3
Substitute the valuesV=433.1433V = \dfrac{4}{3} \cdot 3.14 \cdot 3^3
Cube the radius — not square itV=433.1427V = \dfrac{4}{3} \cdot 3.14 \cdot 27
MultiplyV=113.04V = 113.04

Answer: V=113.04V = 113.04

Example 3: a cone with the diameter given

Find the volume of a cone with diameter 66 and height 1010. Use π3.14\pi \approx 3.14.

Halve the diameter to get the radiusr=62=3r = \dfrac{6}{2} = 3
Write the formulaV=13πr2hV = \dfrac{1}{3} \pi r^2 h
Substitute the valuesV=133.143210V = \dfrac{1}{3} \cdot 3.14 \cdot 3^2 \cdot 10
Square the radius, then multiplyV=13282.6=94.2V = \dfrac{1}{3} \cdot 282.6 = 94.2

Answer: V=94.2V = 94.2

Try one yourself

h=4h=4
r=3r=3

Common questions

Why does the cone formula have a 1/3 in it?

A cone with the same base and height as a cylinder holds exactly one third of the cylinder's volume. The cone narrows to a point, so most of the matching cylinder is empty space around it — one third full, two thirds empty.

Why is the radius cubed for a sphere but squared for a cone?

The cone's r2r^2 comes from the area of its circular base, and the height supplies the third dimension. A sphere has no separate height — the radius controls all three dimensions — so it appears three times: r3r^3.

What if the problem gives the diameter?

Divide by 22 first. Both formulas need the radius. A ball with a diameter of 66 inches has r=3r = 3, and 33 is what gets cubed.

How do I keep 1/3 and 4/3 straight?

Tie each fraction to its shape: the cone is the smaller, pointier solid, so it gets the smaller fraction 13\displaystyle \frac{1}{3}. The sphere bulges out in every direction and gets 43\displaystyle \frac{4}{3}. Writing the formula before substituting catches the mix-up early.

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