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Transforming Exponential Expressions

The same exponential expression can be written with different bases, and each version reveals a different rate. 81t81^t and 34t3^{4t} are equal for every value of tt — but the second version lets you talk about a process that multiplies by 33, four times per unit of tt.

The tool for switching bases is the power of a power rule: (bc)t=bct(b^c)^t = b^{ct}. Write the old base as a power of the new base, then multiply the exponents. The value of the expression never changes — only the way you read it.

The power of a power rule

The rule bct=(bc)tb^{ct} = (b^c)^t works in both directions. Going one way, (34)t=34t\left(3^4\right)^t = 3^{4t} collapses a stacked power into a single exponent. Going the other way, 34t=(34)t=81t3^{4t} = \left(3^4\right)^t = 81^t regroups the exponent to expose a new base.

To rewrite an expression with a target base: write the current base as a power of the target, substitute, and multiply exponents. To rewrite 16t16^t with base 22, note 16=2416 = 2^4, so 16t=(24)t=24t16^t = \left(2^4\right)^t = 2^{4t}.

Why bother: reading a different rate

In a growth model, the base is a per-period multiplier and the exponent counts periods. Changing the base changes the period you are measuring in. An account that grows by (1.08)t(1.08)^t per year satisfies (1.08)t(1.0064)12t(1.08)^t \approx (1.0064)^{12t} — and since 12t12t counts months, the rewritten base 1.00641.0064 shows a monthly growth rate of about 0.64%0.64\%.

Same account, same values, two readings: 8%8\% per year, or roughly 0.64%0.64\% per month. Rewriting the base is how you move between them.

Worked examples

Example 1: rewrite 16t16^t with base 22

Rewrite y=16ty = 16^t using base 22.

Write 1616 as a power of 2216=2416 = 2^4
Substitutey=(24)ty = \left(2^4\right)^t
Power of a power multiplies exponentsy=24ty = 2^{4t}

Answer: y=24ty = 2^{4t}

Example 2: rewrite (1.21)t(1.21)^t with base 1.11.1

Rewrite y=(1.21)ty = (1.21)^t using base 1.11.1.

Recognize the square1.21=(1.1)21.21 = (1.1)^2
Substitutey=((1.1)2)ty = \left((1.1)^2\right)^t
Multiply the exponentsy=(1.1)2ty = (1.1)^{2t}

Answer: y=(1.1)2ty = (1.1)^{2t}

Example 3: a fractional exponent

Which expression is equivalent to 8t3\displaystyle 8^{\frac{t}{3}}?

Write 88 as a power of 228=238 = 2^3
Substitute8t3=(23)t3\displaystyle 8^{\frac{t}{3}} = \left(2^3\right)^{\frac{t}{3}}
Multiply the exponents3t3=t3 \cdot \dfrac{t}{3} = t

Answer: 2t2^t

Try one yourself

Common questions

Does rewriting the base change the value of the expression?

No. 81t81^t and 34t3^{4t} output identical values for every tt. Rewriting only changes the rate you can read directly — the expression stays equivalent.

How do I pick what power to use?

Ask what exponent turns the target base into the current base. For base 33 and current base 8181, solve 3n=813^n = 81 to get n=4n = 4. Then the whole rewrite is 81t=34t81^t = 3^{4t}.

What if the old base is not a whole-number power of the new one?

In Algebra 1 the problems are chosen so it works out — perfect powers like 16=2416 = 2^4 or recognizable squares like 1.21=(1.1)21.21 = (1.1)^2. If nothing fits, double-check for a decimal square or cube before giving up.

Why does the exponent 12t12t mean months?

If tt counts years, then 12t12t counts twelve steps for every year — months. The exponent always counts how many times the base gets applied, so its scale sets the period of the rate.

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