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Surface Area of Pyramids & Cones

Pyramids and cones come to a point, so their sides are triangles or a curved fan rather than rectangles. Their surface area is still one base plus the lateral area, but the lateral area uses a special length called the slant height.

Slant height is the distance up the slanted face, not the straight-up vertical height. Mixing those two up is the number-one error, so this lesson keeps them clearly apart.

The formulas

For a regular pyramid, total surface area = base area + 12P\dfrac{1}{2} P \ell, where PP is the base perimeter and \ell is the slant height. The 12P\dfrac{1}{2} P \ell piece is just the triangular faces added up.

For a cone, total surface area = πr2+πr\pi r^2 + \pi r \ell. The πr2\pi r^2 is the circular base and πr\pi r \ell is the curved lateral surface, again using slant height \ell.

Slant height versus vertical height

The vertical height hh runs straight up from the center of the base to the apex. The slant height \ell runs up the middle of a face. They form a right triangle with half the base, so =h2+(half base)2\ell = \sqrt{h^2 + (\text{half base})^2}.

The figure is that right triangle: the vertical height hh and the base radius rr (or half the base edge for a pyramid) are the legs, and the slant height \ell is the hypotenuse.

If a problem gives you hh but the formula needs \ell, use that right triangle to find \ell first.

hh
rr
\ell

Worked examples

Example 1: a square pyramid

A square pyramid has base edge 66 and slant height 55. Find its total surface area.

Base area plus half perimeter times slants2+12Ps^2 + \tfrac{1}{2} P \ell
Substitute (P = 24)62+12(24)(5)6^2 + \tfrac{1}{2}(24)(5)
Simplify36+60=9636 + 60 = 96

Answer: 9696 square units

Example 2: a cone

Find the surface area of a cone with radius 33 and slant height 77.

Base plus lateral surfaceπr2+πr\pi r^2 + \pi r \ell
Substituteπ(3)2+π(3)(7)\pi(3)^2 + \pi(3)(7)
Simplify9π+21π=30π9\pi + 21\pi = 30\pi

Answer: 30π30\pi square units

Example 3: a cone given the vertical height

Find the surface area of a cone with radius 66 and vertical height 88.

The formula needs slant height, so find it first=h2+r2\ell = \sqrt{h^2 + r^2}
Substitute the height and radius=82+62=100=10\ell = \sqrt{8^2 + 6^2} = \sqrt{100} = 10
Base plus lateral surfaceπ(6)2+π(6)(10)\pi(6)^2 + \pi(6)(10)
Simplify36π+60π=96π36\pi + 60\pi = 96\pi

Answer: 96π96\pi square units

Try one yourself

=5\ell=5
66

Common questions

How do I find slant height if I only know the vertical height?

Use the right triangle inside the solid: =h2+(half the base)2\ell = \sqrt{h^2 + (\text{half the base})^2} for a pyramid, or =h2+r2\ell = \sqrt{h^2 + r^2} for a cone.

Why is the pyramid's lateral area 12P\tfrac{1}{2} P \ell?

Each face is a triangle with base equal to one edge and height \ell. Add all their areas and the total is 12(sum of edges)=12P\tfrac{1}{2}(\text{sum of edges})\ell = \tfrac{1}{2} P \ell.

Does a cone's lateral area really have no 12\tfrac{1}{2}?

Correct — it is πr\pi r \ell with no one-half. The curved fan works out to exactly πr\pi r \ell when you unroll it into a sector.

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