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Some products show up so often they get shortcuts. Squaring a binomial and multiplying conjugates each follow a fixed pattern you can write down without full FOIL.

Recognizing these patterns saves time and prevents the classic mistake of thinking (a+b)2(a + b)^2 equals a2+b2a^2 + b^2 — it does not.

The squared binomial

(a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2 — the square of the first, plus twice the product, plus the square of the last. The middle term 2ab2ab is the one people forget.

(ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2 works the same with a minus on the middle term. Never drop the 2ab2ab.

Difference of squares

(a+b)(ab)=a2b2(a + b)(a - b) = a^2 - b^2. The two middle terms cancel, leaving only the squares.

Spotting a sum times a difference of the same two terms lets you write the answer instantly — no FOIL needed.

Worked examples

Example 1: squaring a binomial

Multiply (2x+5)2(2x + 5)^2.

Square the first(2x)2=4x2(2x)^2 = 4x^2
Twice the product2(2x)(5)=20x2(2x)(5) = 20x
Square the last52=255^2 = 25

Answer: 4x2+20x+254x^2 + 20x + 25

Example 2: difference of squares

Multiply (x+6)(x6)(x + 6)(x - 6).

Middle terms cancelx236x^2 - 36

Answer: x236x^2 - 36

Example 3: squaring a difference

Multiply (3x4)2(3x - 4)^2.

Square the first(3x)2=9x2(3x)^2 = 9x^2
Twice the product, negative this time2(3x)(4)=24x-2(3x)(4) = -24x
Square the last42=164^2 = 16

Answer: 9x224x+169x^2 - 24x + 16

Try one yourself

Common questions

Why isn't (a+b)2(a+b)^2 equal to a2+b2a^2 + b^2?

Squaring a binomial by FOIL produces a middle term: (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2. The 2ab2ab cannot be dropped.

When does difference of squares apply?

When you multiply a sum and a difference of the same two terms, like (x+6)(x6)(x + 6)(x - 6). The result is a2b2a^2 - b^2.

Are these just FOIL shortcuts?

Yes. You can always FOIL, but recognizing the pattern lets you write the answer immediately and avoid sign errors.

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