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Solving One- & Two-Step Inequalities

Solving an inequality like x+5<9x + 5 < 9 or 3x12-3x \leq 12 works almost exactly like solving an equation: use inverse operations on both sides until the variable stands alone.

There is exactly one new rule, and it's the one this whole topic hangs on: when you multiply or divide both sides by a negative number, flip the inequality sign.

Solve it like an equation

Adding or subtracting works with no surprises. To solve x+5<9x + 5 < 9, subtract 55 from both sides: x<4x < 4. Every number less than 44 is a solution.

Multiplying or dividing by a positive number is also safe. Dividing 4x244x \leq -24 by 44 gives x6x \leq -6, and the sign keeps pointing the same way.

The flip rule

When both sides get multiplied or divided by a negative number, the inequality sign reverses direction. Dividing 3x12-3x \leq 12 by 3-3 gives x4x \geq -4 — the \leq flipped to \geq.

Why? Multiplying by a negative reflects every number across zero, which reverses their order. 2<52 < 5 is true, but multiply both sides by 1-1 and you have 2-2 and 5-5 — and 2>5-2 > -5. Flipping the sign keeps the statement true.

The rule is only about multiplying and dividing. Adding or subtracting a negative number never flips the sign.

Two-step inequalities

Use the same order as two-step equations: move the constant first, then deal with the coefficient — flipping only if that last step multiplies or divides by a negative number.

For 2x+7>12x + 7 > 1: subtract 77 to get 2x>62x > -6, then divide by the positive 22 to get x>3x > -3. No flip, because the divisor was positive — the negative on the other side doesn't matter.

Worked examples

Example 1: one step, no flip

Solve x+5<9x + 5 < 9.

Start with the inequalityx+5<9x + 5 < 9
Subtract 55 from both sidesx<4x < 4
Check with a test number: 3+5=8<93 + 5 = 8 < 9

Answer: x<4x < 4

Example 2: divide by a negative

Solve 3x12-3x \leq 12.

Start with the inequality3x12-3x \leq 12
Divide both sides by 3-3 and flip the signx4x \geq -4
Check with a test number: 3(0)=012-3(0) = 0 \leq 12

Answer: x4x \geq -4

Example 3: two steps

Solve 2x+7>12x + 7 > 1.

Start with the inequality2x+7>12x + 7 > 1
Subtract 77 from both sides2x>62x > -6
Divide both sides by 22 — positive, so no flipx>3x > -3

Answer: x>3x > -3

Try one yourself

Common questions

Why does the sign flip when I multiply or divide by a negative?

Multiplying by a negative reflects numbers across zero, and that reverses their order — the bigger number becomes the smaller one. 2<52 < 5 turns into 2>5-2 > -5. Flipping the sign is what keeps the statement true.

Does adding or subtracting a negative number flip the sign?

No. Only multiplying or dividing both sides by a negative number flips it. Solving x3>2x - 3 > 2 by adding 33 keeps the sign: x>5x > 5.

How do I check my answer?

Pick an easy test number from your answer and plug it into the original inequality. For x4x \geq -4, try 00: 3(0)=012-3(0) = 0 \leq 12 is true, so the answer checks. Also test a number outside your answer — it should fail.

How do I graph the answer?

On a number line: open circle for << or >>, closed circle for \leq or \geq, then shade toward the solutions. x>3x > -3 is an open circle at 3-3 with a ray pointing right.

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