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Solving Equations (Special Cases)

Most equations you solve end with the variable equal to one number. But two special cases break that pattern. Sometimes the variable terms cancel completely and leave a statement that is flat-out false, like 7=37 = -3 — that equation has no solution. And sometimes they cancel and leave a statement that is always true, like 15=1515 = 15 — that equation has infinitely many solutions, because every value of the variable works.

The skill in this lesson isn't new solving moves. It's recognizing what it means when the variable disappears on you.

The two special cases

Solve normally: distribute, combine like terms, gather variables on one side. If the variable terms cancel and what's left is a false statement, there is no solution — no number can make the equation true. If what's left is a true statement, there are infinitely many solutions — the two sides were the same expression all along, so every number works.

In 4x+7=4x34x + 7 = 4x - 3, subtracting 4x4x from both sides leaves 7=37 = -3. False, so no solution. In 3(x+5)=3x+153(x + 5) = 3x + 15, distributing gives 3x+15=3x+153x + 15 = 3x + 15; subtracting 3x3x leaves 15=1515 = 15. True, so infinitely many solutions.

What it looks like on a graph

Think of each side of the equation as its own line. A solution is an xx-value where the two lines meet. When an equation has no solution, its two sides are parallel lines — same slope, different starting points — so they never touch.

When an equation has infinitely many solutions, both sides graph as the exact same line, so they "meet" at every single point. And the ordinary case, one solution, is two lines with different slopes crossing exactly once.

-4-3-2-11234-4-3-2-11234xy

Spotting the cases early

You can often see a special case before finishing the algebra. If both sides have the same variable term — like 6x6x on the left and 6x6x on the right — compare the constants. Different constants mean no solution; identical sides mean infinitely many.

But be careful: the coefficients have to match after distributing and combining, not before. 2(3m4)=6m+12(3m - 4) = 6m + 1 doesn't look like a special case until you distribute and see 6m8=6m+16m - 8 = 6m + 1.

Worked examples

Example 1: no solution

Solve 6x+9=6x46x + 9 = 6x - 4.

Start with the equation6x+9=6x46x + 9 = 6x - 4
Subtract 6x6x from both sides — the variable cancels9=49 = -4
9=49 = -4 is false, so no value of xx works

Answer: No solution

Example 2: infinitely many solutions

Solve 4(2x+3)=8x+124(2x + 3) = 8x + 12.

Start with the equation4(2x+3)=8x+124(2x + 3) = 8x + 12
Distribute the 448x+12=8x+128x + 12 = 8x + 12
Subtract 8x8x from both sides12=1212 = 12
12=1212 = 12 is always true, so every value of xx works

Answer: Infinitely many solutions

Example 3: the ordinary case, for contrast

Solve 2x+6=102x + 6 = 10.

Start with the equation2x+6=102x + 6 = 10
Subtract 66 from both sides2x=42x = 4
Divide both sides by 22x=2x = 2
The variable survived, so there is exactly one solution

Answer: x=2x = 2 — one solution

Try one yourself

Common questions

How do I tell no solution and infinitely many solutions apart?

Look at the statement left after the variable cancels. False statement, like 7=37 = -3: no solution. True statement, like 15=1515 = 15: infinitely many solutions.

Is x=0x = 0 the same as no solution?

No — this trips up a lot of students. x=0x = 0 is one perfectly good solution; the number zero works when you plug it in. No solution means the variable vanished and left a false statement, so nothing works.

Did I make a mistake if the variable disappears?

Not necessarily. If your algebra is clean and the variable terms cancel, the equation really is a special case. Re-check your distributing and signs once, then trust the result.

Does "infinitely many solutions" mean any number I pick will work?

Yes. Both sides are the same expression in disguise, so any value of the variable makes them equal. Try one — plug x=1x = 1 into 3(x+5)=3x+153(x + 5) = 3x + 15 and both sides give 1818.

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