Inverse Relations & Functions

A function is a machine: put in an input, get out an output. The inverse function is the same machine run in reverse — it takes the output and hands back the original input. If f(4)=7f(4) = 7, then the inverse, written f−1f^{-1}, satisfies f−1(7)=4f^{-1}(7) = 4. Every input-output pair just trades places.

Inverses matter because most real questions come at a function backwards. A conversion formula turns Celsius into Fahrenheit — but you're handed Fahrenheit and want Celsius. A growth model turns time into population — but you know the population and want the time. Finding the inverse turns "solve for the input every single time" into a formula you use directly.

What an inverse function is

Formally, f−1f^{-1} is the function that reverses ff: whenever f(a)=bf(a) = b, it's also true that f−1(b)=af^{-1}(b) = a. Every point (a,b)(a, b) on the graph of ff becomes the point (b,a)(b, a) on the graph of f−1f^{-1}. Inputs and outputs swap — that's the entire definition.

That coordinate swap has a visual consequence: the graph of f−1f^{-1} is the graph of ff reflected across the line y=xy = x. Fold the plane along that diagonal and the two curves land on each other. Below, a line (blue) and its inverse (red) are mirror images across the dashed line y=xy = x.

One caution on notation: the −1-1 in f−1(x)f^{-1}(x) is not an exponent. f−1(x)f^{-1}(x) means "the inverse function of ff," not 1f(x)\dfrac{1}{f(x)}. The inverse of f(x)=x+4f(x) = x + 4 is f−1(x)=x−4f^{-1}(x) = x - 4, which is nothing like 1x+4\dfrac{1}{x + 4}.

-5-4-3-2-112345-5-4-3-2-112345xy

How to find an inverse: swap and solve

The procedure is two moves. First, write the function as y=…y = \ldots and swap xx and yy — that's the input-output trade built into the definition. Second, solve the new equation for yy. What you get is f−1(x)f^{-1}(x).

For f(x)=2x+6f(x) = 2x + 6: write y=2x+6y = 2x + 6, swap to get x=2y+6x = 2y + 6, then solve — subtract 66 to get x−6=2yx - 6 = 2y, divide by 22 to get y=x2−3y = \dfrac{x}{2} - 3. So f−1(x)=x2−3f^{-1}(x) = \dfrac{x}{2} - 3.

Notice what the inverse does operation by operation: ff multiplies by 22 and then adds 66; f−1f^{-1} subtracts 66 and then divides by 22. The inverse applies the opposite of each operation, in reverse order — the same way you take off shoes before socks.

The mapping below shows f(x)=2x+6f(x) = 2x + 6 sending each input to its output. The inverse simply reverses every arrow: it reads the diagram right-to-left, sending 8→18 \to 1, 10→210 \to 2, and 12→312 \to 3.

Input xOutput f(x)12381012

How to check your inverse

Two functions are inverses exactly when composing them gets you back where you started: f(f−1(x))=xf(f^{-1}(x)) = x and f−1(f(x))=xf^{-1}(f(x)) = x. Run any number through one machine and then the other, and it must come out unchanged. Check both directions — on a test, verifying composition is often the whole problem.

A faster spot-check: pick an easy input. If f(1)=8f(1) = 8, then f−1(8)f^{-1}(8) had better be 11. If it isn't, something went wrong in the swap-and-solve algebra.

One more wrinkle: not every function has an inverse that's a function. If ff sends two different inputs to the same output — like f(x)=x2f(x) = x^2 sending both 22 and −2-2 to 44 — the reverse machine can't decide which input to return. Only one-to-one functions (graphs that pass the horizontal line test) have true inverse functions; that's why x2x^2 only gets an inverse after restricting it to x≥0x \geq 0.

Worked examples

Example 1: a linear function

Find the inverse of f(x)=3x−5f(x) = 3x - 5.

Write with yyy=3x−5y = 3x - 5
Swap xx and yyx=3y−5x = 3y - 5
Add 55 to both sidesx+5=3yx + 5 = 3y
Divide by 33y=x+53y = \dfrac{x + 5}{3}

Answer: f−1(x)=x+53f^{-1}(x) = \dfrac{x + 5}{3} — check: f(4)=7f(4) = 7 and f−1(7)=123=4f^{-1}(7) = \dfrac{12}{3} = 4 ✓

Example 2: the variable is divided

Find the inverse of f(x)=x2+1f(x) = \dfrac{x}{2} + 1.

Write with yyy=x2+1y = \dfrac{x}{2} + 1
Swap xx and yyx=y2+1x = \dfrac{y}{2} + 1
Subtract 11 from both sidesx−1=y2x - 1 = \dfrac{y}{2}
Multiply both sides by 22y=2x−2y = 2x - 2

Answer: f−1(x)=2x−2f^{-1}(x) = 2x - 2 — check: f(6)=4f(6) = 4 and f−1(4)=6f^{-1}(4) = 6 ✓

Example 3: verify two functions are inverses

Show that f(x)=2x+6f(x) = 2x + 6 and g(x)=x2−3g(x) = \dfrac{x}{2} - 3 are inverses.

Compose one direction: substitute gg into fff(g(x))=2(x2−3)+6f(g(x)) = 2\left(\dfrac{x}{2} - 3\right) + 6
Distribute and simplify=x−6+6=x= x - 6 + 6 = x
Compose the other direction: substitute ff into ggg(f(x))=2x+62−3g(f(x)) = \dfrac{2x + 6}{2} - 3
Simplify=x+3−3=x= x + 3 - 3 = x

Answer: Both compositions return xx, so ff and gg are inverses.

Example 4: a cubic function

Find the inverse of f(x)=x3+1f(x) = x^3 + 1.

Write with yy and swapx=y3+1x = y^3 + 1
Subtract 11 from both sidesx−1=y3x - 1 = y^3
Take the cube root of both sidesy=x−13y = \sqrt[3]{x - 1}
Check with a point: f(2)=9f(2) = 9, and f−1(9)=83=2f^{-1}(9) = \sqrt[3]{8} = 2 ✓

Answer: f−1(x)=x−13f^{-1}(x) = \sqrt[3]{x - 1}

Try one yourself

Common questions

Does f−1(x)f^{-1}(x) mean 1f(x)\dfrac{1}{f(x)}?

No — this is the most common notation mistake with inverses. The −1-1 names the inverse function, not a reciprocal. The inverse of f(x)=x+4f(x) = x + 4 is f−1(x)=x−4f^{-1}(x) = x - 4; the reciprocal 1x+4\dfrac{1}{x + 4} is a completely different function.

Does every function have an inverse?

Every function can be reversed as a relation, but the result is only a function when the original is one-to-one — each output comes from exactly one input. Graphically, that's the horizontal line test. f(x)=x2f(x) = x^2 fails it (both 22 and −2-2 give 44), so it only has an inverse function after you restrict its domain.

How are the graphs of ff and f−1f^{-1} related?

They're reflections of each other across the line y=xy = x. Every point (a,b)(a, b) on ff corresponds to the point (b,a)(b, a) on f−1f^{-1}. So if ff passes through (2,3)(2, 3), then f−1f^{-1} must pass through (3,2)(3, 2).

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