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Reflections

A reflection flips a figure over a line — the mirror line — and produces a mirror image. The image is congruent to the original figure: same size, same shape, just flipped. On the coordinate plane, the three mirror lines you'll see most are the xx-axis, the yy-axis, and the line y=xy = x.

The good news is that each of those three reflections has a coordinate rule, so you never have to eyeball the graph. Learn which coordinate changes for each mirror line and reflecting a point becomes a five-second job.

The three reflection rules

Across the xx-axis: (x,y)(x,y)(x, y) \to (x, -y). The xx-coordinate stays the same and the yy-coordinate becomes its opposite.

Across the yy-axis: (x,y)(x,y)(x, y) \to (-x, y). Now the xx-coordinate becomes its opposite and the yy-coordinate stays the same.

Across the line y=xy = x: (x,y)(y,x)(x, y) \to (y, x). No signs change at all — the two coordinates swap places. In the figure below, the point and its image sit on opposite sides of the dashed mirror line y=xy = x, with their coordinates swapped.

-5-4-3-2-112345-5-4-3-2-112345xy
y=xy=x

Why the rules work

A reflection puts the image exactly as far from the mirror line as the original point, but on the other side. Take the point (3,2)(3, 2) and reflect it across the xx-axis. The point sits 22 units above the axis, so its image must sit 22 units below it — that's (3,2)(3, -2). The horizontal position never moved, which is why xx stays the same and only yy changes sign.

The graph below shows that pair. The dashed segment crosses the xx-axis at a right angle, and the axis cuts it exactly in half. Every reflection works this way: the mirror line is the perpendicular bisector of the segment joining a point to its image.

-4-3-2-11234-4-3-2-11234xy

How to keep the rules straight

Students mix up the first two rules constantly, so here is the anchor: the coordinate that matches the axis name is the one that survives. Reflecting across the xx-axis keeps xx and flips yy. Reflecting across the yy-axis keeps yy and flips xx. Think of it as the axis protecting its own letter.

For y=xy = x, don't reach for signs at all — just swap. And if you ever meet y=xy = -x, that reflection swaps and flips both signs: (x,y)(y,x)(x, y) \to (-y, -x).

Worked examples

Example 1: across the x-axis

Reflect the point (4,1)(4, 1) across the xx-axis.

Write the rule for the xx-axis(x,y)(x,y)(x, y) \to (x, -y)
Keep the xx-coordinatex=4x = 4
Flip the sign of the yy-coordinatey=1y = -1

Answer: (4,1)(4, -1)

Example 2: across the y-axis

Reflect the point (5,3)(-5, 3) across the yy-axis.

Write the rule for the yy-axis(x,y)(x,y)(x, y) \to (-x, y)
Flip the sign of the xx-coordinatex=(5)=5x = -(-5) = 5
Keep the yy-coordinatey=3y = 3

Answer: (5,3)(5, 3)

Example 3: across the line y = x

Reflect the point (3,6)(-3, 6) across the line y=xy = x.

Write the rule for y=xy = x(x,y)(y,x)(x, y) \to (y, x)
Swap the coordinates — no signs change(3,6)(6,3)(-3, 6) \to (6, -3)

Answer: (6,3)(6, -3)

Try one yourself

-4-3-2-11234-4-3-2-11234xy
AA

Common questions

Which coordinate changes when I reflect across the x-axis?

The yy-coordinate. The point moves straight up or down to the other side of the axis, so its horizontal position — the xx-coordinate — never changes. The rule is (x,y)(x,y)(x, y) \to (x, -y).

What happens to a point that sits on the mirror line?

Nothing — it maps to itself. A point like (4,0)(4, 0) reflected across the xx-axis is 00 units from the line, so its image is also 00 units from the line, in the same spot.

Is the image the same size as the original?

Yes. A reflection is a rigid motion, so every length and every angle is preserved. The image is congruent to the preimage — the only thing that changes is the orientation, which gets flipped like a mirror image.

How is reflecting across y = -x different from y = x?

Across y=xy = x the coordinates just swap: (x,y)(y,x)(x, y) \to (y, x). Across y=xy = -x they swap and both signs flip: (x,y)(y,x)(x, y) \to (-y, -x). So (2,5)(2, 5) goes to (5,2)(5, 2) across y=xy = x, but to (5,2)(-5, -2) across y=xy = -x.

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