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Domain and Range of Linear & Quadratic Functions

Once you can read domain and range off any graph, lines and parabolas become the easy cases — their answers follow a pattern you can memorize and then verify with a glance. A full line with arrows on both ends covers everything, and a parabola is unlimited side to side but capped in one vertical direction by its vertex.

The skill here is knowing the pattern and knowing why it works, so a test question can't shake you by changing the numbers. Two facts carry the whole lesson: arrows mean the graph goes forever, and a parabola's vertex is either its lowest or highest point.

Linear functions: everything, both ways

A linear function like f(x)=2x1f(x) = 2x - 1 graphs as a line with arrows on both ends. Left to right it never stops, so the domain is all real numbers. Because the line is slanted, it also climbs forever and drops forever, so the range is all real numbers too. In interval notation, both are (,)(-\infty, \infty).

The one exception worth knowing: a horizontal line like f(x)=3f(x) = 3 still has domain all real numbers, but it only ever reaches one height, so its range is just {3}\{3\}.

Quadratic functions: the vertex sets the range

A quadratic function graphs as a parabola. Side to side, a parabola never stops — you can square any number — so the domain of every quadratic is all real numbers.

The range is where the vertex takes over. If the parabola opens upward, the vertex is the lowest point, and the range is every yy from the vertex's height on up: yky \geq k. If it opens downward, the vertex is the highest point, and the range is yky \leq k. The parabola below has vertex (2,1)(2, 1) and opens upward, so its range is y1y \geq 1.

-2-112345612345678xy

The two-question routine

For any line or parabola, ask: does the graph ever stop going left or right? For both families with arrows, no — domain is all real numbers. Then ask: does the graph have a lowest or highest point? A slanted line has neither, so its range is all real numbers. A parabola has exactly one, the vertex, so its range starts or ends there. Only the yy-coordinate of the vertex matters for range — the xx-coordinate never appears in the answer.

Worked examples

Example 1: a slanted line

Find the domain and range of f(x)=3x+4f(x) = -3x + 4.

The graph is a line with arrows on both ends
Left to right it never stopsdomain: all real numbers\text{domain: all real numbers}
It climbs and drops without limitrange: all real numbers\text{range: all real numbers}

Answer: Domain (,)(-\infty, \infty), range (,)(-\infty, \infty)

Example 2: a parabola opening upward

A parabola opens upward with vertex (3,2)(3, -2). Find the domain and range.

Every quadratic accepts every inputdomain: all real numbers\text{domain: all real numbers}
Opening upward means the vertex is the minimum point
The lowest output is the vertex's yy-value, 2-2y2y \geq -2

Answer: Domain (,)(-\infty, \infty), range y2y \geq -2, or [2,)[-2, \infty)

Example 3: a parabola opening downward

A parabola opens downward with vertex (1,6)(-1, 6). Find the domain and range.

Domain is still all real numbers(,)(-\infty, \infty)
Opening downward means the vertex is the maximum point
The highest output is 66, and every yy below it is reachedy6y \leq 6

Answer: Domain (,)(-\infty, \infty), range y6y \leq 6, or (,6](-\infty, 6]

Try one yourself

Common questions

Why is the domain of a parabola all real numbers?

Because you can square any number. A quadratic rule like f(x)=x23f(x) = x^{2} - 3 produces an output no matter what input you hand it, so no xx-value is ever excluded.

How do I tell if the vertex is a minimum or a maximum?

Look at which way the parabola opens. Opening upward makes the vertex the lowest point (a minimum), so the range is yky \geq k. Opening downward makes it the highest point (a maximum), so the range is yky \leq k.

Does the x-coordinate of the vertex affect the range?

No. The range only measures heights, so only the vertex's yy-coordinate shows up. A vertex at (7,2)(7, -2) and a vertex at (100,2)(-100, -2) give the same range for an upward parabola: y2y \geq -2.

Do lines ever have a limited range?

Only horizontal ones. A horizontal line like f(x)=5f(x) = 5 stays at one height forever, so its range is just 55. Any slanted line reaches every height, giving a range of all real numbers.

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