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Division Rule

When you divide two powers with the same base, you keep the base and subtract the exponents: x9x4=x5\dfrac{x^{9}}{x^{4}} = x^{5}. That's the division rule (also called the quotient rule), and it's the mirror image of the multiplication rule.

Here's why it works: x9x4\dfrac{x^{9}}{x^{4}} is nine xx's on top and four on the bottom. Each xx on the bottom cancels one on top, wiping out four pairs and leaving five xx's upstairs — x5x^{5}. Subtracting the exponents is just fast cancelling.

The rule

Same base, divided: keep the base, subtract the exponents — top minus bottom. In symbols, xmxn=xmn\dfrac{x^{m}}{x^{n}} = x^{m-n}.

Just like with multiplication, the base must match, and a plain variable carries an invisible exponent of 11. So a10a=a101=a9\dfrac{a^{10}}{a} = a^{10-1} = a^{9}.

Coefficients divide separately

The numbers in front follow normal division, and only the exponents get subtracted. In 18y76y3\dfrac{18y^{7}}{6y^{3}}, divide 18÷6=318 \div 6 = 3 and subtract 73=47 - 3 = 4, giving 3y43y^{4}.

With more than one variable, subtract each variable's exponents on its own: 20a5b84a2b3\dfrac{20a^{5}b^{8}}{4a^{2}b^{3}} gives coefficient 55, then a52=a3a^{5-2} = a^{3} and b83=b5b^{8-3} = b^{5}, so the answer is 5a3b55a^{3}b^{5}.

Order matters in the subtraction

Always subtract the bottom exponent from the top exponent. If the bigger exponent is on the bottom, the subtraction comes out negative — x3x7=x4\dfrac{x^{3}}{x^{7}} = x^{-4} — and a negative exponent means the power really lives in the denominator: 1x4\dfrac{1}{x^{4}}. That's the negative exponent rule, which gets its own lesson.

Worked examples

Example 1: same base, subtract the exponents

Simplify x9x4\dfrac{x^{9}}{x^{4}}.

Same base xx, so keep it and subtract the exponentsx94x^{9-4}
Subtractx5x^{5}

Answer: x5x^{5}

Example 2: coefficients divide, exponents subtract

Simplify 24x68x2\dfrac{24x^{6}}{8x^{2}}.

Divide the coefficients24÷8=324 \div 8 = 3
Subtract the exponents on xx62=46 - 2 = 4
Put them together3x43x^{4}

Answer: 3x43x^{4}

Example 3: two variables

Simplify 20a5b84a2b3\dfrac{20a^{5}b^{8}}{4a^{2}b^{3}}.

Divide the coefficients20÷4=520 \div 4 = 5
Subtract the exponents on aa52=35 - 2 = 3
Subtract the exponents on bb83=58 - 3 = 5
Put them together5a3b55a^{3}b^{5}

Answer: 5a3b55a^{3}b^{5}

Try one yourself

Common questions

Why subtract the exponents instead of dividing them?

Because every factor on the bottom cancels one matching factor on top. Nine xx's over four xx's leaves 94=59 - 4 = 5 of them. Subtraction counts what survives the cancelling.

What if the exponents are equal?

Then everything cancels: x4x4=x0=1\dfrac{x^{4}}{x^{4}} = x^{0} = 1. Any nonzero base to the zero power is 11, and this is exactly where that fact comes from.

What if the bottom exponent is bigger?

The subtraction gives a negative exponent: x2x5=x3\dfrac{x^{2}}{x^{5}} = x^{-3}. Rewrite it with a positive exponent as 1x3\dfrac{1}{x^{3}} — the leftover factors are on the bottom.

Do I subtract the coefficients too?

No — coefficients divide normally. In 12x53x2\dfrac{12x^{5}}{3x^{2}}, the 1212 and 33 divide to 44 while the exponents subtract to 33, giving 4x34x^{3}.

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