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Distributing Polynomials

Distributing means multiplying one term by everything inside a set of parentheses. In 4(3x+2)4(3x + 2), the 44 multiplies both the 3x3x and the 22, giving 12x+812x + 8. You have seen this with plain numbers — now the term out front can have a variable too, like 3x(x+5)3x(x + 5).

Two rules carry the whole topic: multiply the coefficients, and add the exponents on matching variables. So 3xx=3x23x \cdot x = 3x^{2}, because xx=x1+1=x2x \cdot x = x^{1+1} = x^{2}. Once those two moves are automatic, distributing any monomial across any polynomial is the same short routine.

Distribute to every term

The term in front must reach every term inside the parentheses — no exceptions. For 3x(x2+2x4)3x(x^{2} + 2x - 4) that means three separate products: 3xx2=3x33x \cdot x^{2} = 3x^{3}, then 3x2x=6x23x \cdot 2x = 6x^{2}, then 3x(4)=12x3x \cdot (-4) = -12x. The answer is 3x3+6x212x3x^{3} + 6x^{2} - 12x.

For each product, handle the numbers and the variables separately: multiply the coefficients, then add the exponents on the variable. In 3x2x3x \cdot 2x, the coefficients give 32=63 \cdot 2 = 6 and the variables give xx=x2x \cdot x = x^{2}, so the product is 6x26x^{2}.

The most common mistake is multiplying only the first term inside and forgetting the rest. Draw arrows from the front term to each inside term if it helps — every arrow is one product.

Distributing a negative

When the front term is negative, its sign travels with it into every product. In 3(x24x+5)-3(x^{2} - 4x + 5): 3x2=3x2-3 \cdot x^{2} = -3x^{2}, then 3(4x)=+12x-3 \cdot (-4x) = +12x, then 35=15-3 \cdot 5 = -15. Every sign in the answer changes from the original: 3x2+12x15-3x^{2} + 12x - 15.

Slow down on the middle terms. A negative times a negative is positive, and that flip is exactly where rushed work goes wrong.

Distribute first, then combine like terms

Many problems mix distribution with extra terms, like 2(x2+3x)5x2(x^{2} + 3x) - 5x. Distribute first to get 2x2+6x5x2x^{2} + 6x - 5x, then combine the like terms: 6x5x=x6x - 5x = x. The simplified answer is 2x2+x2x^{2} + x.

The order matters — you cannot combine anything with a term that is still locked inside parentheses.

Worked examples

Example 1: a monomial times a trinomial

Multiply 3x(x2+2x4)3x(x^{2} + 2x - 4).

Distribute to the first term3xx2=3x33x \cdot x^{2} = 3x^{3}
Distribute to the second term3x2x=6x23x \cdot 2x = 6x^{2}
Distribute to the third term3x(4)=12x3x \cdot (-4) = -12x

Answer: 3x3+6x212x3x^{3} + 6x^{2} - 12x

Example 2: a negative front term

Multiply 2x(4x23x+5)-2x(4x^{2} - 3x + 5).

Distribute to the first term2x4x2=8x3-2x \cdot 4x^{2} = -8x^{3}
Distribute to the second term — negative times negative2x(3x)=6x2-2x \cdot (-3x) = 6x^{2}
Distribute to the third term2x5=10x-2x \cdot 5 = -10x

Answer: 8x3+6x210x-8x^{3} + 6x^{2} - 10x

Example 3: distribute, then combine like terms

Simplify 5(2x2+3x1)3x25(2x^{2} + 3x - 1) - 3x^{2}.

Distribute the 5510x2+15x53x210x^{2} + 15x - 5 - 3x^{2}
Combine the x2x^{2} terms10x23x2=7x210x^{2} - 3x^{2} = 7x^{2}
Nothing else combines7x2+15x57x^{2} + 15x - 5

Answer: 7x2+15x57x^{2} + 15x - 5

Try one yourself

Common questions

Why does 3xx3x \cdot x equal 3x23x^{2} and not 3x3x?

Because xxx \cdot x means x1x1x^{1} \cdot x^{1}, and when you multiply matching bases you add the exponents: x1+1=x2x^{1+1} = x^{2}. The coefficient 33 just rides along.

Do I add or multiply the coefficients?

Multiply them — this is multiplication, not combining like terms. In 4x3x4x \cdot 3x, the coefficients give 43=124 \cdot 3 = 12 and the variables give x2x^{2}, so the product is 12x212x^{2}.

What if there are two variables, like 2xy(3x+y)2xy(3x + y)?

Same rules, one variable at a time. 2xy3x=6x2y2xy \cdot 3x = 6x^{2}y and 2xyy=2xy22xy \cdot y = 2xy^{2}, so the answer is 6x2y+2xy26x^{2}y + 2xy^{2}. Exponents only add on matching letters.

How can I check a distribution?

Factor your answer back: pull the front term out of every term of your result and you should land exactly on the original parentheses. For instance, 12x+8=4(3x+2)12x + 8 = 4(3x + 2) confirms Example-style work.

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