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Circumference & Arc Length

An arc is a piece of a circle's edge, and a sector is a pizza-slice piece of its inside. Both are measured with the same trick: figure out what fraction of the whole circle you have, then take that fraction of the whole circle's measurement. The fraction always comes from the central angle — the angle at the center between the two radii — divided by 360360^\circ.

That's the entire topic. Arc length is a fraction of the circumference 2πr2\pi r, and sector area is the same fraction of the area πr2\pi r^2. If you can find the fraction and you know the two circle formulas, every arc and sector problem is two lines of work.

One idea: the fraction of the circle

A central angle of θ\theta degrees cuts off θ360\dfrac{\theta}{360} of the circle. In the figure below, the 120120^\circ angle claims 120360=13\dfrac{120}{360} = \dfrac{1}{3} of the circle — one third of the edge and one third of the inside. Reduce the fraction before doing anything else; it keeps the arithmetic small.

The two radii and the angle between them define both the arc (the curved edge between AA and BB) and the sector (the slice enclosed by the two radii and that arc).

rr
120120^\circ
OO
AA
BB

Arc length: a fraction of the circumference

Arc length is a distance along the edge, so it comes from the circumference: =θ3602πr\ell = \dfrac{\theta}{360} \cdot 2\pi r. A 9090^\circ arc is a quarter of the circumference, a 6060^\circ arc is a sixth, and so on.

Don't confuse arc length with arc measure. Arc measure is just the central angle in degrees — a 6060^\circ arc has measure 6060^\circ in a circle of any size. Arc length is an actual distance, and it grows with the radius: a 6060^\circ arc on a bigger circle is longer.

Sector area: the same fraction of the area

Sector area comes from the circle's area: A=θ360πr2A = \dfrac{\theta}{360} \cdot \pi r^2. Same fraction, different base formula.

That's also how to keep the two formulas straight: length questions use the length formula 2πr2\pi r, and area questions use the area formula πr2\pi r^2. If your sector answer doesn't involve r2r^2 somewhere, you likely used the circumference by mistake.

Worked examples

Example 1: arc length

A circle has a radius of 66. Find the length of an arc with a central angle of 6060^\circ.

Write the arc length formula=θ3602πr\ell = \dfrac{\theta}{360} \cdot 2\pi r
Substitute and reduce the fraction=603602π(6)=1612π\ell = \dfrac{60}{360} \cdot 2\pi(6) = \dfrac{1}{6} \cdot 12\pi
Simplify=2π\ell = 2\pi

Answer: =2π6.3\ell = 2\pi \approx 6.3

Example 2: arc length from a diameter

A circle has a diameter of 1010. Find the length of an arc with a central angle of 144144^\circ.

Halve the diameter to get the radiusr=102=5r = \dfrac{10}{2} = 5
Find the fraction of the circle144360=25\dfrac{144}{360} = \dfrac{2}{5}
Multiply by the circumference=252π(5)=2510π\ell = \dfrac{2}{5} \cdot 2\pi(5) = \dfrac{2}{5} \cdot 10\pi
Simplify=4π\ell = 4\pi

Answer: =4π12.6\ell = 4\pi \approx 12.6

Example 3: sector area

A circle has a radius of 66. Find the area of a sector with a central angle of 120120^\circ.

Write the sector area formulaA=θ360πr2A = \dfrac{\theta}{360} \cdot \pi r^2
Substitute and reduce the fractionA=120360π(6)2=1336πA = \dfrac{120}{360} \cdot \pi(6)^2 = \dfrac{1}{3} \cdot 36\pi
SimplifyA=12πA = 12\pi

Answer: A=12π37.7A = 12\pi \approx 37.7 square units

Example 4: working backward to the angle

A sector of a circle with radius 66 has an area of 6π6\pi. Find its central angle.

Set up the sector area formula6π=θ360π(6)26\pi = \dfrac{\theta}{360} \cdot \pi(6)^2
Simplify the right side6π=θ36036π6\pi = \dfrac{\theta}{360} \cdot 36\pi
Divide both sides by 36π36\piθ360=6π36π=16\dfrac{\theta}{360} = \dfrac{6\pi}{36\pi} = \dfrac{1}{6}
Multiply both sides by 360360θ=60\theta = 60^\circ

Answer: θ=60\theta = 60^\circ

Try one yourself

99
8080^\circ
OO
AA
BB
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Common questions

What's the difference between arc measure and arc length?

Arc measure is the central angle in degrees — it ignores the size of the circle. Arc length is a real distance along the edge, so it depends on the radius: =θ3602πr\ell = \dfrac{\theta}{360} \cdot 2\pi r. Two arcs can have the same measure but very different lengths.

How do I remember which formula uses 2πr2\pi r and which uses πr2\pi r^2?

Match the type of answer. Arc length is a distance, so it takes a fraction of the distance around the circle, 2πr2\pi r. Sector area is an area, so it takes the same fraction of πr2\pi r^2. Both fractions are θ360\dfrac{\theta}{360}.

What if the angle is given in radians?

Radians make arc length even simpler: s=rθs = r\theta, with no fraction at all. That works because a radian is defined so a full turn is 2π2\pi radians. The sector area version is A=12r2θA = \dfrac{1}{2}r^2\theta. If the angle is in degrees, stick with the θ360\dfrac{\theta}{360} formulas.

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